PO.MBE.F.Oil.SI
Description
Calculates underground withdrawal for oil reservoir, [m3]. F = Np*(Bo + (Rp-Rs)*Bg) + Wp*Bw (SI units).
Formula
=LAMBDA(Np, Bo, Rp, Rs, Bg, Wp, Bw, LET(
Np_bbl, PO.UnitConverter(Np, "m3", "bbl"),
Rp_scfSTB, PO.UnitConverter(Rp, "sm3/sm3", "scf/STB"),
Rs_scfSTB, PO.UnitConverter(Rs, "sm3/sm3", "scf/STB"),
Bg_bblft3, PO.UnitConverter(Bg, "m3/m3", "bbl/ft3"),
Wp_bbl, PO.UnitConverter(Wp, "m3", "bbl"),
result_bbl, PO.MBE.F.Oil(Np_bbl, Bo, Rp_scfSTB, Rs_scfSTB, Bg_bblft3, Wp_bbl, Bw),
PO.UnitConverter(result_bbl, "bbl", "m3")))Parameters
| Parameter | Unit | Description |
|---|---|---|
Np |
m3 | Cumulative oil production, [m3] |
Bo |
- | Current oil FVF, [rm3/sm3] |
Rp |
sm3/sm3 | Cumulative producing GOR = Gp/Np, [sm3/sm3] |
Rs |
sm3/sm3 | Current solution GOR, [sm3/sm3] |
Bg |
rm3/sm3 | Current gas FVF, [rm3/sm3] |
Wp |
m3 | Cumulative water production, [m3] |
Bw |
- | Water FVF, [rm3/sm3] |
Examples
| Invocation | Expected |
|---|---|
=PO.MBE.F.Oil.SI(159000, 1.2, 1, 88.9, 0.005, 15900, 1.01) |
136978.5 |