# Payne method for intercompartmental flow in tight gas reservoirs

## Input(s)

k: Permeability $$(\mathrm{mD})$$

$$\mathrm{T}$$: Temperature $$\left({ }^{\circ} \mathrm{R}\right)$$

A: Cross-Sectional Area $$\left(\mathrm{ft}^{2}\right)$$

L: Distance between the Center of the Two Compartments (ft)

$$\mathrm{m}\left(\mathrm{P}_{1}\right)$$: Gas Pseudo pressure in Compartment (Tank) $$1\left(\mathrm{psi}^{2} / \mathrm{cP}\right)$$

$$\mathrm{m}\left(\mathrm{P}_{2}\right)$$: Gas Pseudo pressure in Compartment (Tank) $$\left(\mathrm{psi}^{2} / \mathrm{cP}\right)$$

## Output(s)

$$\mathrm{Q}_{12}$$: Flow Rate between the Two Compartments (SCF/day)

## Formula(s)

$\mathrm{Q}_{12}=\left(\frac{0.111924 * \mathrm{k} * \mathrm{~A}}{\mathrm{~T} * \mathrm{~L}}\right) *\left(\mathrm{~m}\left(\mathrm{P}_{1}\right)-\mathrm{m}\left(\mathrm{P}_{2}\right)\right)$

## Reference(s)

Ahmed, T., McKinney, P.D. 2005. Advanced Reservoir Engineering, Gulf Publishing of Elsevier, Chapter: 3, Page: 234, 235.

## Related

### Reservoir flow for gas flow in a formation

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