Dimensionless time - Myhill and Stegemeier's method

Input(s)

Ms\mathrm{M}_{\mathrm{s}}: Volumetric Heat Capacity of Steam (btu/ft3 K)\left(\mathrm{btu} / \mathrm{ft}^{3} \mathrm{~K}\right)

MR\mathrm{M}_{\mathrm{R}}: Volumetric Heat Capacity of the Reservoir (btu/ft ft3 K\mathrm{ft}^{3} \mathrm{~K} )

αs\alpha_{\mathrm{s}}: Overburden Heat Transfer Coefficient (ft2/d)\left(\mathrm{ft}^{2} / \mathrm{d}\right)

ht\mathrm{h}_{\mathrm{t}}: Thickness of Column (ft)

t: Time (day)

Output(s)

tD\mathrm{t}_{\mathrm{D}}: Dimensionless Time (dimensionless)

Formula(s)

tD=4(MsMR)2(αsht2)t\mathrm{t}_{\mathrm{D}}=4 *\left(\frac{\mathrm{M}_{\mathrm{s}}}{\mathrm{M}_{\mathrm{R}}}\right)^{2} *\left(\frac{\alpha_{\mathrm{s}}}{h_{t}^{2}}\right) * \mathrm{t}

Reference(s)

Prats, M. 1986. Thermal Recovery. Society of Petroleum Engineers, New York, Chapter: 5, Page: 44.


Related

An unhandled error has occurred. Reload 🗙