Side force at bit in anisotropic formation

Input(s)

p: Buoyed Weight of Drill Collar (ppf)

E: Modulus of Elasticity (psi)

I: Moment of inertia of Drill Collar (in. 4{ }^{4} )

r: Radial Clearance Between Hole and Collar (ft)

θ\theta: inclination Angle (degree)

W: Weight on Bit (lbf)

Output(s)

F: Side Force on Bit (lbf)

Formula(s)

F=p((EI)0.5)((W24)((24rEIpsin(θ))0.75)((1.5rEIpsin(θ))0.25))\mathrm{F}=\mathrm{p} *\left((\mathrm{E} * \mathrm{I})^{0.5}\right) *\left(\left(\frac{\mathrm{W}}{24}\right) *\left(\left(\frac{24 * \mathrm{r}}{\mathrm{E} * \mathrm{I} * \mathrm{p} * \sin (\theta)}\right)^{0.75}\right)-\left(\left(\frac{1.5 * \mathrm{r}}{\mathrm{E} * \mathrm{I} * \mathrm{p} * \sin (\theta)}\right)^{0.25}\right)\right)

Reference(s)

Samuel. E Robello. 501 Solved Problems and Calculations for Drilling Operations. Sigma Quadrant. 2015. Houston, Texas, Page: 378.


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