Equivalent area of pipe subject to uniform axial force

Input(s)

Ab\mathrm{A}_{\mathrm{b}}: Area of Body (\left(\right. in. 2)\left.^{2}\right)

Aj\mathrm{A}_{\mathrm{j}}: Area of Joint ( in. 2{ }^{2} )

α\alpha: Length Factor for Pipe Body (fraction)

Output(s)

ApA_{p} :Area of Pipe ( in. 2{ }^{2} )

Formula(s)

Ap=Ab Ajα Ab(1α) Aj\mathrm{A}_{\mathrm{p}}=\frac{\mathrm{A}_{\mathrm{b}} * \mathrm{~A}_{\mathrm{j}}}{\alpha * \mathrm{~A}_{\mathrm{b}} *(1-\alpha) * \mathrm{~A}_{\mathrm{j}}}

Reference(s)

Samuel. E Robello. 501 Solved Problems and Calculations for Drilling Operations. Sigma Quadrant. 2015. Houston, Texas, Page: 44.


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