Polar moment of inertia

Input(s)

JbJ_{b}: Polar Moment of Inertia of Pipe Body (ft4)\left(\mathrm{ft}^{4}\right)

JjJ_{j}: Polar Moment of Inertia of Tool Joint (ft4)\left(\mathrm{ft}^{4}\right)

L: Length of Pipe (ft)(\mathrm{ft})

1: Joint Tool Length (ft)

Output(s)

JpJ_{p}: Polar Moment of Inertia of Pipe (ft4)\left(\mathrm{ft}^{4}\right)

Formula(s)

Jp=JbJj(LlL)Jj(lL)JbJ_{p}=\frac{J_{b} * J_{j}}{\left(\frac{L-l}{L}\right) * J_{j} *\left(\frac{l}{L}\right) * J_{b}}

Reference(s)

Samuel. E Robello. 501 Solved Problems and Calculations for Drilling Operations. Sigma Quadrant. 2015. Houston, Texas, Page: 356.

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